-[8z-(19z+3)]=3+(10z+9)

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Solution for -[8z-(19z+3)]=3+(10z+9) equation:


Simplifying
-1[8z + -1(19z + 3)] = 3 + (10z + 9)

Reorder the terms:
-1[8z + -1(3 + 19z)] = 3 + (10z + 9)
-1[8z + (3 * -1 + 19z * -1)] = 3 + (10z + 9)
-1[8z + (-3 + -19z)] = 3 + (10z + 9)

Reorder the terms:
-1[-3 + 8z + -19z] = 3 + (10z + 9)

Combine like terms: 8z + -19z = -11z
-1[-3 + -11z] = 3 + (10z + 9)
[-3 * -1 + -11z * -1] = 3 + (10z + 9)
[3 + 11z] = 3 + (10z + 9)

Reorder the terms:
3 + 11z = 3 + (9 + 10z)

Remove parenthesis around (9 + 10z)
3 + 11z = 3 + 9 + 10z

Combine like terms: 3 + 9 = 12
3 + 11z = 12 + 10z

Solving
3 + 11z = 12 + 10z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10z' to each side of the equation.
3 + 11z + -10z = 12 + 10z + -10z

Combine like terms: 11z + -10z = 1z
3 + 1z = 12 + 10z + -10z

Combine like terms: 10z + -10z = 0
3 + 1z = 12 + 0
3 + 1z = 12

Add '-3' to each side of the equation.
3 + -3 + 1z = 12 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 12 + -3
1z = 12 + -3

Combine like terms: 12 + -3 = 9
1z = 9

Divide each side by '1'.
z = 9

Simplifying
z = 9

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